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HOW TO’s .. Print Duplicates

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Certainly! Let’s find those duplicates. Here are a few ways to identify duplicate elements in a list:

1. Using Naive Method (Nested Loops):
   • You can use two nested loops to compare each element with every other element in the list. If any pair of elements match, they are duplicates.
   • Example:my_list = [10, 12, 14, 10, 16, 14, 18] for i in range(len(my_list)): for j in range(i + 1, len(my_list)): if my_list[i] == my_list[j]: print(my_list[i]) Output: 10, 14
2. Using a Set:
   • Create an empty set to store duplicate elements.
   • Loop through the list and add elements to the set if their count in the list is greater than 1.
   • Example:my_list = [10, 12, 14, 10, 16, 14, 18] duplicate = set() for num in my_list: if my_list.count(num) > 1: duplicate.add(num) print(duplicate) Output: {10, 14}
3. Using a Single Loop and count() Method:
   • Loop through the list and check if each element appears more than once.
   • If so, add it to another list (avoiding duplicates in the new list).
   • Example:my_list = [10, 12, 14, 10, 16, 14, 18] duplicate = [] for num in my_list: if my_list.count(num) > 1 and num not in duplicate: duplicate.append(num) print(duplicate) Output: [10, 14]
4. Using Counter() Method:
   • The Counter() method counts the occurrences of each element in the list.
   • Use a list comprehension to extract elements with a count greater than 1.
   • Example:from collections import Counter my_list = [10, 12, 14, 10, 16, 14, 18] duplicates = [item for item, count in Counter(my_list).items() if count > 1] print(duplicates) Output: [10, 14]

Feel free to choose the method that suits your needs! 😊

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